Respiratory Organs
Oโ is needed to break down food for energy and COโ is the harmful by-product. Breathing is the exchange of atmospheric Oโ with COโ produced by the cells.
Our body cells run on food and oxygen, like a tiny fire. Burning food gives them energy but also makes smoke (COโ). Breathing is how we bring in fresh Oโ and throw out COโ.
- The exchange of Oโ from the atmosphere with COโ produced by cells is called
- Respiration only
- Breathing
- Catabolism
- Glycolysis
Show answer
Answer: Breathing. Breathing = pulmonary ventilation + gas exchange. Cellular respiration is the energy-release step inside cells. - COโ is produced during
- Anabolic reactions
- Catabolic reactions
- Photosynthesis
- Excretion only
Show answer
Answer: Catabolic reactions. Catabolic reactions break large molecules โ release energy + COโ. - Which gas needs to be continuously supplied to cells?
- COโ
- Oโ
- Nโ
- Hโ
Show answer
Answer: Oโ. Cells need oxygen for aerobic respiration (electron transport).
Mechanisms of breathing vary among animals. Sponges/coelenterates use simple diffusion; insects use a network of tracheal tubes; aquatic arthropods/molluscs use gills (branchial respiration); terrestrial vertebrates use lungs (pulmonary respiration). Frogs also use moist skin (cutaneous respiration).
Different animals have different gear for breathing โ bugs have little air pipes, fish have feathery gills, land animals like us have lungs. Frogs cheat โ they breathe through their wet skin too.
- Tracheal tubes for respiration are found in
- Earthworm
- Insects
- Fish
- Frog
Show answer
Answer: Insects. Insects ventilate body tissues via tiny tracheal tubes opening at spiracles. - Cutaneous respiration is seen in
- Bird
- Mammal
- Frog
- Insect
Show answer
Answer: Frog. Amphibian skin is thin, moist and vascular โ allows gas exchange. - Gills for branchial respiration are used by
- Reptiles
- Aquatic arthropods and molluscs
- Birds
- Mammals
Show answer
Answer: Aquatic arthropods and molluscs. Gills are vascularised structures specialised for water-air gas exchange.
Human respiratory system: external nostrils โ nasal chamber โ pharynx โ larynx (with epiglottis) โ trachea โ primary, secondary, tertiary bronchi โ bronchioles โ alveoli. Larynx (sound box) is supported by cartilage. The trachea divides at the 5th thoracic vertebra.
Air enters through the nose, slides down the throat past a flap (epiglottis) that keeps food out, goes through the wind-pipe and branches into smaller and smaller pipes ending in tiny balloons (alveoli) where the magic exchange happens.
- Trachea divides at the level of
- 3rd thoracic vertebra
- 5th thoracic vertebra
- 7th thoracic vertebra
- 9th thoracic vertebra
Show answer
Answer: 5th thoracic vertebra. Tracheal bifurcation occurs at T5 into right and left primary bronchi. - Sound is produced in the
- Pharynx
- Larynx
- Trachea
- Bronchi
Show answer
Answer: Larynx. Larynx is the sound box; vocal cords vibrate to make sound. - Epiglottis prevents
- Air entering trachea
- Food entering larynx
- Sound production
- Gas exchange
Show answer
Answer: Food entering larynx. During swallowing, the epiglottis closes the glottis.
The lungs are covered by a double-layered pleura with pleural fluid in between to reduce friction. The thoracic chamber is air-tight โ bounded by vertebrae (dorsally), sternum (ventrally), ribs (laterally) and the dome-shaped diaphragm (below).
Each lung is wrapped in two slippery sheets like a sandwich bag, with oil between them so they don't stick. The chest is a sealed box that gets bigger and smaller to suck and push air.
- Pleural fluid
- Helps gas exchange
- Reduces friction
- Carries hormones
- Filters dust
Show answer
Answer: Reduces friction. It lubricates the pleural sheets during lung movements. - The dome-shaped muscle below the lungs is
- Sternum
- Diaphragm
- Intercostal
- Pectoral
Show answer
Answer: Diaphragm. Diaphragm contracts to enlarge the thoracic cavity. - The thoracic cavity is closed at the lower side by the
- Ribs
- Vertebrae
- Sternum
- Diaphragm
Show answer
Answer: Diaphragm. Diaphragm forms the floor of the thoracic chamber.
Two functional parts: conducting part (nostrils โ terminal bronchioles) transports, cleans, humidifies and warms the air; respiratory/exchange part (alveoli + ducts) is where Oโ and COโ actually move across the membrane.
The pipe network has two jobs โ first it acts like the airport corridors that just move you, then the alveoli are the gates where the actual swap takes place.
- Conducting part of the respiratory system
- Carries out gas exchange
- Transports, cleans, humidifies and warms air
- Produces sound
- Stores air
Show answer
Answer: Transports, cleans, humidifies and warms air. Function summary of the conducting zone. - Site of actual gas exchange is
- Bronchi
- Trachea
- Alveoli
- Larynx
Show answer
Answer: Alveoli. Alveoli have thin walls and rich capillaries. - Terminal bronchioles belong to
- Conducting part
- Exchange part
- Both
- Neither
Show answer
Answer: Conducting part. Exchange begins at the respiratory bronchioles and alveoli.
Mechanism of Breathing
Breathing has two stages: inspiration (air drawn in) and expiration (air pushed out). Air moves because of a pressure gradient between the lungs (intra-pulmonary pressure) and the atmosphere.
To suck air in we make our lungs bigger so the pressure inside drops below outside โ air rushes in. To push air out we shrink the lungs so the pressure inside is higher than outside.
- Inspiration occurs when intra-pulmonary pressure is
- Greater than atmospheric
- Less than atmospheric
- Equal to atmospheric
- Zero
Show answer
Answer: Less than atmospheric. Negative pressure draws atmospheric air in. - During expiration, the intra-pulmonary pressure is
- Less than atmospheric
- Equal
- Slightly greater than atmospheric
- Zero
Show answer
Answer: Slightly greater than atmospheric. Higher inside-pressure pushes air out. - The pressure gradient required for breathing is generated by
- Diaphragm and intercostal muscles
- Heart
- Pleura
- Larynx
Show answer
Answer: Diaphragm and intercostal muscles. These muscles change thoracic volume to change pressure.
During inspiration, the diaphragm contracts (increases antero-posterior volume) and the external intercostal muscles lift ribs and sternum (dorso-ventral increase). Thoracic and lung volume rise; intra-pulmonary pressure falls โ air enters.
To breathe IN, two helpers act: the diaphragm pulls down to give the lungs more head-room and the chest muscles lift the ribs forward. Bigger lungs = lower pressure = fresh air rushes in.
- During inspiration, diaphragm
- Contracts and flattens
- Relaxes and curves up
- Stays still
- Disappears
Show answer
Answer: Contracts and flattens. Flattening enlarges thoracic volume. - External intercostal muscles cause
- Lowering of ribs
- Raising of ribs and sternum
- No change
- Both inspiration and expiration
Show answer
Answer: Raising of ribs and sternum. They lift the ribcage outward and upward. - Volume of thoracic chamber increases in
- Antero-posterior axis only
- Dorso-ventral axis only
- Both axes
- Neither axis
Show answer
Answer: Both axes. Diaphragm contributes to AP axis; intercostals contribute to DV axis.
During expiration, the diaphragm and intercostal muscles relax. Diaphragm returns to its dome shape; ribs lower. Thoracic and pulmonary volume decrease; intra-pulmonary pressure rises above atmospheric โ air goes out. A healthy human breathes 12โ16 times per minute.
Breathing OUT is easy โ let go of the diaphragm and the chest muscles. They snap back, lungs shrink, pressure rises and air gets pushed out. We do this 12 to 16 times a minute without thinking.
- Resting respiratory rate of a healthy adult is
- 6โ8 per minute
- 12โ16 per minute
- 20โ30 per minute
- 40โ50 per minute
Show answer
Answer: 12โ16 per minute. Standard NCERT value for adults at rest. - During quiet expiration
- Muscles contract
- Muscles relax
- Diaphragm flattens
- Intercostals lift ribs
Show answer
Answer: Muscles relax. Quiet expiration is passive recoil; muscles relax. - Volume of air involved in breathing is estimated using a
- Sphygmomanometer
- Spirometer
- Stethoscope
- Spectroscope
Show answer
Answer: Spirometer. Spirometer measures lung volumes/capacities.
Respiratory volumes โ Tidal Volume (TV): air inspired/expired during normal breathing โ 500 mL. Inspiratory Reserve Volume (IRV): extra inspiration โ 2500โ3000 mL. Expiratory Reserve Volume (ERV): extra expiration โ 1000โ1100 mL. Residual Volume (RV): air left after a forceful expiration โ 1100โ1200 mL.
Four cups of air to remember: TV is the everyday cup (500 mL), IRV the big extra gulp (about 3 L), ERV the strong blow-out (about 1 L), RV the air that can never leave the lungs (about 1.1 L).
- Tidal volume is approximately
- 300 mL
- 500 mL
- 1200 mL
- 3000 mL
Show answer
Answer: 500 mL. Standard NCERT value of TV. - Volume of air remaining in lungs after a forced expiration
- IRV
- ERV
- TV
- Residual Volume
Show answer
Answer: Residual Volume. RV is about 1100โ1200 mL. - Forced extra inspiration after a normal one is
- TV
- ERV
- IRV
- RV
Show answer
Answer: IRV. Inspiratory Reserve Volume โ 2500โ3000 mL.
Respiratory capacities (derived) โ Inspiratory Capacity IC = TV+IRV; Expiratory Capacity EC = TV+ERV; Functional Residual Capacity FRC = ERV+RV; Vital Capacity VC = ERV+TV+IRV; Total Lung Capacity TLC = RV+ERV+TV+IRV = VC+RV.
Adding the cups gives 'capacities': IC = TV+IRV, EC = TV+ERV, FRC = ERV+RV. Vital Capacity is the most useful โ the biggest amount you can willingly move in or out. Total Lung Capacity is everything including the never-leaves part.
- Vital Capacity equals
- TV + IRV
- TV + ERV
- TV + IRV + ERV
- TV + IRV + ERV + RV
Show answer
Answer: TV + IRV + ERV. VC excludes residual volume. - Functional Residual Capacity is
- ERV + RV
- TV + IRV
- TV + RV
- VC + RV
Show answer
Answer: ERV + RV. Air left after a normal expiration. - Total Lung Capacity equals
- IRV+TV
- VC+RV
- FRC + IRV
- EC + RV
Show answer
Answer: VC+RV. TLC = Vital Capacity + Residual Volume.
Exchange of Gases
Alveoli are the primary site of gas exchange. Exchange between blood and tissues also occurs by simple diffusion driven by pressure (concentration) gradients. Solubility of gases and thickness of the diffusion membrane affect the rate.
Tiny balloons (alveoli) trade gases with blood by simple physics โ gas moves from where there's lots of it to where there's less, no pumps needed. Thin walls and gas-friendly water (solubility) speed it up.
- Exchange of gases occurs primarily by
- Active transport
- Simple diffusion
- Endocytosis
- Bulk flow
Show answer
Answer: Simple diffusion. Driven by partial pressure gradients across thin alveolar membrane. - Rate of gas exchange depends on
- Pressure gradient and solubility
- Membrane thickness
- Surface area
- All of these
Show answer
Answer: All of these. Fick's law: rate โ area ร ฮP / thickness. - Primary site of gas exchange is
- Trachea
- Bronchi
- Bronchioles
- Alveoli
Show answer
Answer: Alveoli. Alveoli have thin walls and dense capillary network.
Partial pressures (mm Hg): Atmospheric pOโ โ 159, pCOโ โ 0.3; Alveolar pOโ โ 104, pCOโ โ 40; Deoxygenated blood pOโ โ 40, pCOโ โ 45; Oxygenated blood pOโ โ 95, pCOโ โ 40; Tissues pOโ โ 40, pCOโ โ 45.
Each gas has its own 'pressure number' that says how much of it is there. Oโ is high in alveoli (104) and low in tissues (40) โ so it flows from alveoli to tissues. COโ is the opposite โ high in tissues (45) and low in alveoli (40) โ so it flows out.
- Partial pressure of Oโ in alveoli is approximately (mm Hg)
- 40
- 95
- 104
- 159
Show answer
Answer: 104. Slightly less than atmospheric because of mixing with residual air. - pCOโ in tissues is approximately
- 0.3
- 40
- 45
- 159
Show answer
Answer: 45. Higher than in blood, allowing COโ to diffuse into the blood. - Difference between atmospheric and alveolar pOโ is approximately
- 55 mm Hg
- 100 mm Hg
- 159 mm Hg
- 0 mm Hg
Show answer
Answer: 55 mm Hg. 159 โ 104 = 55 mm Hg.
Solubility of COโ is 20โ25 times higher than that of Oโ, so even with a tiny pressure difference COโ diffuses much faster across the membrane.
COโ swims through the watery membrane much more easily than Oโ โ about 20 to 25 times faster โ so even a small push gets it across.
- Solubility of COโ in blood compared to Oโ is
- Equal
- 20โ25 times higher
- Half
- 100 times higher
Show answer
Answer: 20โ25 times higher. High solubility lets COโ transfer fast despite small gradient. - Why does COโ diffuse faster than Oโ?
- Higher pressure gradient
- Higher solubility
- Larger molecule
- Same speed
Show answer
Answer: Higher solubility. Pressure gradient for Oโ is actually larger โ but COโ's solubility wins. - If membrane thickness doubles, diffusion rate
- Doubles
- Halves
- Stays same
- Becomes zero
Show answer
Answer: Halves. Rate โ 1/thickness.
The diffusion membrane has three layers: thin squamous epithelium of alveoli, endothelium of alveolar capillaries, and basement substance in between. Total thickness < 1 mm. This thin barrier favours rapid gas exchange.
The wall between air and blood is super thin โ three paper-thin layers stacked, all under a millimetre. That's why gases zip across so easily.
- Diffusion membrane consists of
- 1 layer
- 2 layers
- 3 layers
- 4 layers
Show answer
Answer: 3 layers. Alveolar epithelium + basement substance + capillary endothelium. - Total thickness of the alveolar diffusion membrane is
- Much less than 1 mm
- About 1 cm
- About 1 m
- Variable
Show answer
Answer: Much less than 1 mm. Standard NCERT value. - The squamous epithelium of alveoli is
- Thick
- Thin
- Ciliated
- Glandular
Show answer
Answer: Thin. Thinness is essential for efficient diffusion.
Transport of Gases
Blood transports Oโ and COโ. About 97% of Oโ is carried by RBCs and 3% dissolved in plasma. About 20โ25% of COโ is carried by RBCs (as carbamino-haemoglobin), 70% as bicarbonate (HCOโโป) and 7% dissolved in plasma.
Blood is the delivery truck. Oโ rides almost entirely inside red blood cells (97%). COโ takes three rides โ mostly as bicarbonate in plasma (70%), some stuck to haemoglobin (20-25%), a little dissolved (7%).
- Percentage of Oโ carried by RBCs is approximately
- 50%
- 70%
- 85%
- 97%
Show answer
Answer: 97%. 97% bound to haemoglobin; 3% dissolved in plasma. - COโ is mainly carried in blood as
- Bicarbonate
- Carbamino-haemoglobin
- Dissolved COโ
- Carbonic acid
Show answer
Answer: Bicarbonate. About 70% of COโ travels as HCOโโป. - Approximate percentage of COโ as carbamino-haemoglobin
- 7%
- 20โ25%
- 70%
- 100%
Show answer
Answer: 20โ25%. Carbamino-haemoglobin carries 20โ25% of COโ.
Haemoglobin is a red, iron-containing pigment in RBCs. Each Hb molecule can carry up to 4 molecules of Oโ reversibly to form oxyhaemoglobin. Binding depends mainly on pOโ; pCOโ, Hโบ and temperature also affect it.
Hb is like a 4-seater bus โ each molecule can carry up to 4 oxygens. The bus loads up when pOโ is high (in the lungs) and drops off passengers when pOโ is low (in tissues).
- Each Hb molecule can carry up to
- 1
- 2
- 3
- 4
Show answer
Answer: 4. Four haem groups bind four Oโ. - Hb is rich in
- Calcium
- Zinc
- Iron
- Magnesium
Show answer
Answer: Iron. Feยฒโบ in haem binds Oโ reversibly. - Binding of Oโ to Hb is primarily related to
- pCOโ
- pOโ
- Temperature
- Hโบ
Show answer
Answer: pOโ. High pOโ โ more loading.
The Oxygen Dissociation Curve is sigmoid. In alveoli (high pOโ, low pCOโ, low Hโบ, lower T) โ favours formation of oxyhaemoglobin. In tissues (low pOโ, high pCOโ, high Hโบ, higher T) โ favours dissociation. Every 100 mL of oxygenated blood delivers about 5 mL Oโ to tissues.
The curve looks like a stretched 'S'. In lungs, conditions favour loading Oโ onto Hb; in working tissues, conditions favour unloading. Acidity, heat, and COโ all push Oโ off Hb (Bohr effect).
- Oxygen dissociation curve is
- Linear
- Hyperbolic
- Sigmoid
- Parabolic
Show answer
Answer: Sigmoid. S-shape due to cooperative binding of Oโ. - In tissues, the curve shifts
- Left
- Right
- No shift
- Inverted
Show answer
Answer: Right. High COโ/Hโบ/T = right shift = Oโ released more easily (Bohr effect). - 100 mL of oxygenated blood delivers approximately
- 1 mL
- 5 mL
- 20 mL
- 50 mL
Show answer
Answer: 5 mL. Tissues receive about 5 mL Oโ per 100 mL blood under normal conditions.
COโ transport via bicarbonate: at the tissue, COโ + HโO โ HโCOโ โ HCOโโป + Hโบ catalysed by carbonic anhydrase in RBCs. At alveoli the reaction reverses to release COโ. Every 100 mL of deoxygenated blood delivers about 4 mL COโ to alveoli.
COโ at tissues gets quickly turned into HCOโโป by a fast enzyme (carbonic anhydrase) inside red cells, then travels in plasma. In the lungs the enzyme reverses it back to COโ to be breathed out.
- Enzyme catalysing COโ + HโO โ HโCOโ is
- Catalase
- Carbonic anhydrase
- Cytochrome c
- Aldolase
Show answer
Answer: Carbonic anhydrase. Located mainly in RBCs. - 100 mL deoxygenated blood delivers approximately
- 1 mL COโ
- 4 mL COโ
- 20 mL COโ
- 75 mL COโ
Show answer
Answer: 4 mL COโ. Standard NCERT value. - Bohr effect refers to
- Acidity decreases Oโ binding
- Acidity increases Oโ binding
- Heat increases binding
- Temperature decreases binding
Show answer
Answer: Acidity decreases Oโ binding. Higher Hโบ/COโ shifts curve right โ Oโ released to tissues.
Regulation of Respiration
The respiratory rhythm centre in the medulla primarily maintains respiratory rhythm. The pneumotaxic centre in the pons can moderate it by reducing inspiration duration.
Brain has two control rooms โ the medulla sets the basic in-and-out rhythm, the pons can change how long each breath lasts.
- Respiratory rhythm centre is located in
- Pons
- Cerebellum
- Medulla
- Cerebrum
Show answer
Answer: Medulla. Medulla oblongata houses the main respiratory centre. - Pneumotaxic centre is in the
- Medulla
- Pons
- Spinal cord
- Hypothalamus
Show answer
Answer: Pons. Pons modulates the medullary rhythm. - Pneumotaxic centre can
- Reduce duration of inspiration
- Increase TV
- Increase RV
- Stop breathing
Show answer
Answer: Reduce duration of inspiration. It alters respiratory rate by shortening inspiration.
A chemosensitive area adjacent to the rhythm centre is highly sensitive to COโ and Hโบ. Increased levels activate it; it signals the rhythm centre to eliminate COโ. Receptors at the aortic arch and carotid artery also detect COโ/Hโบ. Role of Oโ in regulation is insignificant.
Tiny sensors in the brain (and major arteries) keep watch on COโ and acid levels in blood. If COโ rises, breathing speeds up automatically. Oxygen has almost no role in this control.
- Chemosensitive area is sensitive to
- Oโ and Nโ
- COโ and Hโบ
- Glucose
- Water
Show answer
Answer: COโ and Hโบ. Detects rise in COโ and acidity. - Peripheral chemoreceptors are present in
- Aortic arch and carotid artery
- Lungs
- Liver
- Kidney
Show answer
Answer: Aortic arch and carotid artery. These send signals to the rhythm centre. - Role of oxygen in respiratory regulation is
- Major
- Insignificant
- Equal to COโ
- Only at high altitudes
Show answer
Answer: Insignificant. NCERT statement: Oโ has insignificant regulatory role.
Disorders of the Respiratory System
Asthma โ difficulty in breathing causing wheezing due to inflammation of bronchi and bronchioles. Emphysema โ chronic disorder where alveolar walls are damaged, reducing respiratory surface; major cause is cigarette smoking.
Asthma narrows the small air pipes so air whistles through them (wheeze). Emphysema breaks the alveolar walls โ less surface for swapping gases. Smoking is the worst trigger for emphysema.
- Asthma involves inflammation of
- Alveoli
- Trachea
- Bronchi and bronchioles
- Pleura
Show answer
Answer: Bronchi and bronchioles. Narrowed airways cause wheezing. - Emphysema damages
- Trachea
- Larynx
- Alveolar walls
- Pleura
Show answer
Answer: Alveolar walls. Reduces total surface area for gas exchange. - Major cause of emphysema is
- Bacterial infection
- Cigarette smoking
- Cold air
- Pollution
Show answer
Answer: Cigarette smoking. Smoking destroys elastic alveolar tissue.
Occupational respiratory disorders โ long exposure to dust (e.g., stone-grinding) causes inflammation that progresses to fibrosis (proliferation of fibrous tissues) and serious lung damage. Workers should wear protective masks.
Working in dusty places like stone-grinding plants can clog and scar the lungs with fibres over years. Masks are essential.
- Long exposure to industrial dust causes
- Asthma
- Emphysema
- Fibrosis
- Pneumonia
Show answer
Answer: Fibrosis. Fibrous tissue proliferation damages lungs. - Occupational respiratory disorders are common in
- Office workers
- Stone-grinders
- Teachers
- Cooks
Show answer
Answer: Stone-grinders. Grinding/stone-breaking work produces fine dust. - Prevention of occupational lung disorders includes
- Exercise
- Vaccination
- Wearing protective masks
- Eating fibre-rich diet
Show answer
Answer: Wearing protective masks. Physical barrier to dust inhalation.
Exceptions to Remember
- Frogs are unique among vertebrates โ they can use cutaneous (skin) respiration in addition to pulmonary respiration.
- Insects bypass blood for Oโ transport โ tracheal tubes deliver air directly to tissues.
- Oโ has an insignificant role in regulation of respiration โ COโ and Hโบ dominate.
- COโ is 20โ25 times more soluble than Oโ in blood โ small pressure gradient still enables fast exchange.
- Lower invertebrates (sponges, coelenterates, flatworms) exchange gases by simple diffusion over the body surface.
- The lung surface itself does not have muscles โ pulmonary volume can only be changed indirectly via thoracic volume.
- Each Hb molecule has 4 binding sites, so the dissociation curve is sigmoid (cooperative binding).
Scientists & Key Contributions
Christian Bohr (1855โ1911)
Danish physiologist; discovered the Bohr effect โ COโ and Hโบ shift the Oโ-dissociation curve to the right, releasing Oโ in tissues.
John Scott Haldane (1860โ1936)
Studied gas exchange in lungs and respiratory regulation by COโ. The 'Haldane effect' is named after him.
Felix Hoppe-Seyler
Crystallised haemoglobin and coined the name; founded modern biochemistry of respiratory pigments.
Alfonso Corti (1822โ1888)
Italian anatomist who described the organ of Corti in the cochlea; unit chapter opener.
Key Examples & Values
| Example / Value | Significance |
|---|---|
| Tidal volume (TV) | 500 mL per breath at rest |
| Inspiratory Reserve Volume (IRV) | 2500โ3000 mL |
| Expiratory Reserve Volume (ERV) | 1000โ1100 mL |
| Residual Volume (RV) | 1100โ1200 mL |
| Vital Capacity (VC) | โ 4000โ4500 mL = ERV + TV + IRV |
| Total Lung Capacity (TLC) | โ 5000โ6000 mL = VC + RV |
| Resting respiratory rate | 12โ16 breaths per minute |
| Atmospheric pOโ / pCOโ | 159 / 0.3 mm Hg |
| Alveolar pOโ / pCOโ | 104 / 40 mm Hg |
| Tissue pOโ / pCOโ | 40 / 45 mm Hg |
| Solubility ratio COโ : Oโ | โ 20โ25 : 1 |
| Hb molecules per Oโ carried | 4 Oโ per Hb (max) |
| Oxygen carried per 100 mL blood | โ 5 mL delivered to tissues |
| COโ delivered per 100 mL deoxygenated blood | โ 4 mL to alveoli |
| Distribution of COโ in blood | 70% bicarbonate, 20โ25% carbamino-Hb, 7% dissolved |
| Distribution of Oโ in blood | 97% with Hb, 3% dissolved in plasma |
NCERT Exercises โ Explained & Answered
Q1Define vital capacity. What is its significance?
Q2State the volume of air remaining in the lungs after a normal breathing.
Q3Diffusion of gases occurs in the alveolar region only and not in the other parts of respiratory system. Why?
Q4What are the major transport mechanisms for COโ? Explain.
Q5Compare atmospheric and alveolar pOโ/pCOโ.
Q6Explain the process of inspiration under normal conditions.
Q7How is respiration regulated?
Q8What is the effect of pCOโ on oxygen transport?
Q9What happens to the respiratory process in a man going up a hill?
Q10What is the site of gaseous exchange in an insect?
Q11Define oxygen dissociation curve. Can you suggest any reason for its sigmoidal pattern?
Q12Have you heard about hypoxia? Try to gather information about it, and discuss with your friends.
Q13Distinguish between (a) IRV and ERV (b) Inspiratory and Expiratory capacity (c) Vital capacity and Total lung capacity.
Q14What is Tidal volume? Find out the Tidal volume (approximate value) for a healthy human in an hour.
High-Yield Points for NEET
- Trachea bifurcates at the level of the 5th thoracic vertebra into two primary bronchi.
- Pleural fluid reduces friction on the lung surface.
- Conducting part: nostrils โ terminal bronchioles. Respiratory part: alveoli + alveolar ducts.
- Inspiration is ACTIVE (muscles contract); quiet expiration is PASSIVE (muscles relax).
- Diaphragm contributes to antero-posterior expansion; intercostals to dorso-ventral.
- Memorise: TV 500, IRV 3000, ERV 1100, RV 1200; VC โ 4500, TLC โ 6000 mL.
- Atmospheric, alveolar and tissue pOโ: 159, 104, 40 mm Hg.
- Atmospheric, alveolar and tissue pCOโ: 0.3, 40, 45 mm Hg.
- Oโ in blood: 97% as oxyhaemoglobin, 3% dissolved.
- COโ in blood: 70% bicarbonate, 20โ25% carbamino-Hb, 7% dissolved.
- Carbonic anhydrase (in RBCs) catalyses both forward and reverse reactions of COโ โ HCOโโป.
- Oxygen dissociation curve is sigmoid. Right shift (Bohr) helps tissues; left shift (in alveoli) loads Oโ.
- Each Hb molecule binds up to 4 Oโ.
- Respiratory rhythm centre โ medulla; pneumotaxic centre โ pons; chemosensitive area โ sensitive to COโ + Hโบ.
- Oโ has negligible direct role in respiratory rhythm regulation.
- Asthma โ inflammation of bronchi/bronchioles. Emphysema โ alveolar wall damage (smoking).
- Solubility of COโ in blood is 20โ25 times that of Oโ.
- Diffusion membrane = 3 layers + total thickness < 1 mm.
- VC reflects pulmonary health โ falls in restrictive (fibrosis) and obstructive (emphysema) diseases.
- Aortic arch and carotid body sensors detect blood COโ/Hโบ for reflex regulation.
โ๏ธ Quick Comparisons โ Side-by-Side Reference
VS Inspiration vs Expiration
| Property | Inspiration | Expiration |
|---|---|---|
| Type at rest | Active | Passive |
| Diaphragm | Contracts and flattens | Relaxes; dome-shaped |
| External intercostals | Contract; ribs lift | Relax; ribs lower |
| Thoracic volume | Increases | Decreases |
| Intra-pulmonary pressure | Less than atmospheric | Slightly greater than atmospheric |
| Air flow | Atmosphere โ lungs | Lungs โ atmosphere |
VS IRV vs ERV
| Property | IRV | ERV |
|---|---|---|
| Full name | Inspiratory Reserve Volume | Expiratory Reserve Volume |
| Definition | Extra air inspired forcibly after normal inspiration | Extra air expired forcibly after normal expiration |
| Volume | 2500โ3000 mL | 1000โ1100 mL |
| Direction | In | Out |
VS Inspiratory Capacity (IC) vs Expiratory Capacity (EC)
| Property | IC | EC |
|---|---|---|
| Formula | TV + IRV | TV + ERV |
| Value | ~3500 mL | ~1500 mL |
| Meaning | Total inspired after normal expiration | Total expired after normal inspiration |
VS Vital Capacity (VC) vs Total Lung Capacity (TLC)
| Property | VC | TLC |
|---|---|---|
| Formula | ERV + TV + IRV | VC + RV |
| Value | ~4500 mL | ~5500โ6000 mL |
| Includes RV? | No | Yes |
| Clinical use | Pulmonary function index | Total air-containing capacity |
VS Conducting Part vs Respiratory Part
| Property | Conducting | Respiratory / Exchange |
|---|---|---|
| Structures | Nostrils โ terminal bronchioles | Alveoli + alveolar ducts |
| Function | Transport, clean, humidify, warm air | Gas diffusion (Oโ/COโ) |
| Cartilage | Present in most | Absent |
| Cilia / mucus | Present | Absent |
VS Oโ vs COโ โ Partial Pressures (mm Hg)
| Region | pOโ | pCOโ |
|---|---|---|
| Atmospheric air | 159 | 0.3 |
| Alveolar air | 104 | 40 |
| Deoxygenated blood | 40 | 45 |
| Oxygenated blood | 95 | 40 |
| Tissues | 40 | 45 |
Gradient is OPPOSITE for Oโ and COโ. NEET classic.
VS Oxygen vs Carbon Dioxide Transport
| Property | Oxygen | Carbon Dioxide |
|---|---|---|
| % in plasma (dissolved) | 3% | 7% |
| % with Hb | 97% (oxyhaemoglobin) | 20โ25% (carbamino-Hb) |
| % as bicarbonate | 0 | 70% |
| Solubility | Low | 20โ25ร higher than Oโ |
| Loading site | Alveoli | Tissues |
VS Bohr effect โ Tissue vs Alveolar conditions
| Property | Tissues | Alveoli |
|---|---|---|
| pOโ | Low | High |
| pCOโ | High | Low |
| Hโบ concentration | High | Low |
| Temperature | Higher | Lower |
| Effect on OโโHb | Dissociation | Formation |
| Curve shift | Right | Left |
VS Respiratory Rhythm Centre vs Pneumotaxic Centre
| Property | Rhythm Centre | Pneumotaxic Centre |
|---|---|---|
| Location | Medulla | Pons |
| Primary role | Sets basal respiratory rhythm | Modulates rhythm (shortens inspiration) |
| Effect | Drives breathing | Alters respiratory rate |
VS Asthma vs Emphysema
| Property | Asthma | Emphysema |
|---|---|---|
| Cause | Inflammation, allergens | Cigarette smoking, chronic exposure |
| Site of damage | Bronchi and bronchioles | Alveolar walls |
| Reversibility | Reversible (with bronchodilators) | Irreversible |
| Main symptom | Wheezing, breathing difficulty | Breathlessness, decreased surface area |
VS Breathing in different animals
| Animal | Respiratory organ | Type |
|---|---|---|
| Sponges, coelenterates, flatworms | Body surface | Simple diffusion |
| Earthworm | Moist cuticle | Cutaneous diffusion |
| Insects | Tracheal tubes | Tracheal respiration |
| Aquatic arthropods, molluscs | Gills | Branchial respiration |
| Fishes | Gills | Branchial |
| Frogs | Lungs + moist skin | Pulmonary + cutaneous |
| Reptiles, birds, mammals | Lungs | Pulmonary |