NCERT Class 11 Biology โ€ข Chapter 14

Breathing and Exchange of Gases

๐Ÿ“„ Source PDF: kebo114.pdf

Read it line by line. Each line is explained as if you are 10, then 3 NEET-style questions follow. The end has Exceptions, Scientists, Examples & Values, Exercises, High-Yield Points and a โš–๏ธ Quick Comparisons set.

14.1

Respiratory Organs

1

Oโ‚‚ is needed to break down food for energy and COโ‚‚ is the harmful by-product. Breathing is the exchange of atmospheric Oโ‚‚ with COโ‚‚ produced by the cells.

๐Ÿง’ Easy Explanation

Our body cells run on food and oxygen, like a tiny fire. Burning food gives them energy but also makes smoke (COโ‚‚). Breathing is how we bring in fresh Oโ‚‚ and throw out COโ‚‚.

๐Ÿ“ NEET-style Questions
  1. The exchange of Oโ‚‚ from the atmosphere with COโ‚‚ produced by cells is called
    1. Respiration only
    2. Breathing
    3. Catabolism
    4. Glycolysis
    Show answerAnswer: Breathing. Breathing = pulmonary ventilation + gas exchange. Cellular respiration is the energy-release step inside cells.
  2. COโ‚‚ is produced during
    1. Anabolic reactions
    2. Catabolic reactions
    3. Photosynthesis
    4. Excretion only
    Show answerAnswer: Catabolic reactions. Catabolic reactions break large molecules โ†’ release energy + COโ‚‚.
  3. Which gas needs to be continuously supplied to cells?
    1. COโ‚‚
    2. Oโ‚‚
    3. Nโ‚‚
    4. Hโ‚‚
    Show answerAnswer: Oโ‚‚. Cells need oxygen for aerobic respiration (electron transport).
2

Mechanisms of breathing vary among animals. Sponges/coelenterates use simple diffusion; insects use a network of tracheal tubes; aquatic arthropods/molluscs use gills (branchial respiration); terrestrial vertebrates use lungs (pulmonary respiration). Frogs also use moist skin (cutaneous respiration).

๐Ÿง’ Easy Explanation

Different animals have different gear for breathing โ€” bugs have little air pipes, fish have feathery gills, land animals like us have lungs. Frogs cheat โ€” they breathe through their wet skin too.

๐Ÿ“ NEET-style Questions
  1. Tracheal tubes for respiration are found in
    1. Earthworm
    2. Insects
    3. Fish
    4. Frog
    Show answerAnswer: Insects. Insects ventilate body tissues via tiny tracheal tubes opening at spiracles.
  2. Cutaneous respiration is seen in
    1. Bird
    2. Mammal
    3. Frog
    4. Insect
    Show answerAnswer: Frog. Amphibian skin is thin, moist and vascular โ€” allows gas exchange.
  3. Gills for branchial respiration are used by
    1. Reptiles
    2. Aquatic arthropods and molluscs
    3. Birds
    4. Mammals
    Show answerAnswer: Aquatic arthropods and molluscs. Gills are vascularised structures specialised for water-air gas exchange.
3

Human respiratory system: external nostrils โ†’ nasal chamber โ†’ pharynx โ†’ larynx (with epiglottis) โ†’ trachea โ†’ primary, secondary, tertiary bronchi โ†’ bronchioles โ†’ alveoli. Larynx (sound box) is supported by cartilage. The trachea divides at the 5th thoracic vertebra.

๐Ÿง’ Easy Explanation

Air enters through the nose, slides down the throat past a flap (epiglottis) that keeps food out, goes through the wind-pipe and branches into smaller and smaller pipes ending in tiny balloons (alveoli) where the magic exchange happens.

๐Ÿ“ NEET-style Questions
  1. Trachea divides at the level of
    1. 3rd thoracic vertebra
    2. 5th thoracic vertebra
    3. 7th thoracic vertebra
    4. 9th thoracic vertebra
    Show answerAnswer: 5th thoracic vertebra. Tracheal bifurcation occurs at T5 into right and left primary bronchi.
  2. Sound is produced in the
    1. Pharynx
    2. Larynx
    3. Trachea
    4. Bronchi
    Show answerAnswer: Larynx. Larynx is the sound box; vocal cords vibrate to make sound.
  3. Epiglottis prevents
    1. Air entering trachea
    2. Food entering larynx
    3. Sound production
    4. Gas exchange
    Show answerAnswer: Food entering larynx. During swallowing, the epiglottis closes the glottis.
4

The lungs are covered by a double-layered pleura with pleural fluid in between to reduce friction. The thoracic chamber is air-tight โ€” bounded by vertebrae (dorsally), sternum (ventrally), ribs (laterally) and the dome-shaped diaphragm (below).

๐Ÿง’ Easy Explanation

Each lung is wrapped in two slippery sheets like a sandwich bag, with oil between them so they don't stick. The chest is a sealed box that gets bigger and smaller to suck and push air.

๐Ÿ“ NEET-style Questions
  1. Pleural fluid
    1. Helps gas exchange
    2. Reduces friction
    3. Carries hormones
    4. Filters dust
    Show answerAnswer: Reduces friction. It lubricates the pleural sheets during lung movements.
  2. The dome-shaped muscle below the lungs is
    1. Sternum
    2. Diaphragm
    3. Intercostal
    4. Pectoral
    Show answerAnswer: Diaphragm. Diaphragm contracts to enlarge the thoracic cavity.
  3. The thoracic cavity is closed at the lower side by the
    1. Ribs
    2. Vertebrae
    3. Sternum
    4. Diaphragm
    Show answerAnswer: Diaphragm. Diaphragm forms the floor of the thoracic chamber.
5

Two functional parts: conducting part (nostrils โ†’ terminal bronchioles) transports, cleans, humidifies and warms the air; respiratory/exchange part (alveoli + ducts) is where Oโ‚‚ and COโ‚‚ actually move across the membrane.

๐Ÿง’ Easy Explanation

The pipe network has two jobs โ€” first it acts like the airport corridors that just move you, then the alveoli are the gates where the actual swap takes place.

๐Ÿ“ NEET-style Questions
  1. Conducting part of the respiratory system
    1. Carries out gas exchange
    2. Transports, cleans, humidifies and warms air
    3. Produces sound
    4. Stores air
    Show answerAnswer: Transports, cleans, humidifies and warms air. Function summary of the conducting zone.
  2. Site of actual gas exchange is
    1. Bronchi
    2. Trachea
    3. Alveoli
    4. Larynx
    Show answerAnswer: Alveoli. Alveoli have thin walls and rich capillaries.
  3. Terminal bronchioles belong to
    1. Conducting part
    2. Exchange part
    3. Both
    4. Neither
    Show answerAnswer: Conducting part. Exchange begins at the respiratory bronchioles and alveoli.
14.2

Mechanism of Breathing

1

Breathing has two stages: inspiration (air drawn in) and expiration (air pushed out). Air moves because of a pressure gradient between the lungs (intra-pulmonary pressure) and the atmosphere.

๐Ÿง’ Easy Explanation

To suck air in we make our lungs bigger so the pressure inside drops below outside โ€” air rushes in. To push air out we shrink the lungs so the pressure inside is higher than outside.

๐Ÿ“ NEET-style Questions
  1. Inspiration occurs when intra-pulmonary pressure is
    1. Greater than atmospheric
    2. Less than atmospheric
    3. Equal to atmospheric
    4. Zero
    Show answerAnswer: Less than atmospheric. Negative pressure draws atmospheric air in.
  2. During expiration, the intra-pulmonary pressure is
    1. Less than atmospheric
    2. Equal
    3. Slightly greater than atmospheric
    4. Zero
    Show answerAnswer: Slightly greater than atmospheric. Higher inside-pressure pushes air out.
  3. The pressure gradient required for breathing is generated by
    1. Diaphragm and intercostal muscles
    2. Heart
    3. Pleura
    4. Larynx
    Show answerAnswer: Diaphragm and intercostal muscles. These muscles change thoracic volume to change pressure.
2

During inspiration, the diaphragm contracts (increases antero-posterior volume) and the external intercostal muscles lift ribs and sternum (dorso-ventral increase). Thoracic and lung volume rise; intra-pulmonary pressure falls โ†’ air enters.

๐Ÿง’ Easy Explanation

To breathe IN, two helpers act: the diaphragm pulls down to give the lungs more head-room and the chest muscles lift the ribs forward. Bigger lungs = lower pressure = fresh air rushes in.

๐Ÿ“ NEET-style Questions
  1. During inspiration, diaphragm
    1. Contracts and flattens
    2. Relaxes and curves up
    3. Stays still
    4. Disappears
    Show answerAnswer: Contracts and flattens. Flattening enlarges thoracic volume.
  2. External intercostal muscles cause
    1. Lowering of ribs
    2. Raising of ribs and sternum
    3. No change
    4. Both inspiration and expiration
    Show answerAnswer: Raising of ribs and sternum. They lift the ribcage outward and upward.
  3. Volume of thoracic chamber increases in
    1. Antero-posterior axis only
    2. Dorso-ventral axis only
    3. Both axes
    4. Neither axis
    Show answerAnswer: Both axes. Diaphragm contributes to AP axis; intercostals contribute to DV axis.
3

During expiration, the diaphragm and intercostal muscles relax. Diaphragm returns to its dome shape; ribs lower. Thoracic and pulmonary volume decrease; intra-pulmonary pressure rises above atmospheric โ†’ air goes out. A healthy human breathes 12โ€“16 times per minute.

๐Ÿง’ Easy Explanation

Breathing OUT is easy โ€” let go of the diaphragm and the chest muscles. They snap back, lungs shrink, pressure rises and air gets pushed out. We do this 12 to 16 times a minute without thinking.

๐Ÿ“ NEET-style Questions
  1. Resting respiratory rate of a healthy adult is
    1. 6โ€“8 per minute
    2. 12โ€“16 per minute
    3. 20โ€“30 per minute
    4. 40โ€“50 per minute
    Show answerAnswer: 12โ€“16 per minute. Standard NCERT value for adults at rest.
  2. During quiet expiration
    1. Muscles contract
    2. Muscles relax
    3. Diaphragm flattens
    4. Intercostals lift ribs
    Show answerAnswer: Muscles relax. Quiet expiration is passive recoil; muscles relax.
  3. Volume of air involved in breathing is estimated using a
    1. Sphygmomanometer
    2. Spirometer
    3. Stethoscope
    4. Spectroscope
    Show answerAnswer: Spirometer. Spirometer measures lung volumes/capacities.
4

Respiratory volumes โ€” Tidal Volume (TV): air inspired/expired during normal breathing โ‰ˆ 500 mL. Inspiratory Reserve Volume (IRV): extra inspiration โ‰ˆ 2500โ€“3000 mL. Expiratory Reserve Volume (ERV): extra expiration โ‰ˆ 1000โ€“1100 mL. Residual Volume (RV): air left after a forceful expiration โ‰ˆ 1100โ€“1200 mL.

๐Ÿง’ Easy Explanation

Four cups of air to remember: TV is the everyday cup (500 mL), IRV the big extra gulp (about 3 L), ERV the strong blow-out (about 1 L), RV the air that can never leave the lungs (about 1.1 L).

๐Ÿ“ NEET-style Questions
  1. Tidal volume is approximately
    1. 300 mL
    2. 500 mL
    3. 1200 mL
    4. 3000 mL
    Show answerAnswer: 500 mL. Standard NCERT value of TV.
  2. Volume of air remaining in lungs after a forced expiration
    1. IRV
    2. ERV
    3. TV
    4. Residual Volume
    Show answerAnswer: Residual Volume. RV is about 1100โ€“1200 mL.
  3. Forced extra inspiration after a normal one is
    1. TV
    2. ERV
    3. IRV
    4. RV
    Show answerAnswer: IRV. Inspiratory Reserve Volume โ‰ˆ 2500โ€“3000 mL.
5

Respiratory capacities (derived) โ€” Inspiratory Capacity IC = TV+IRV; Expiratory Capacity EC = TV+ERV; Functional Residual Capacity FRC = ERV+RV; Vital Capacity VC = ERV+TV+IRV; Total Lung Capacity TLC = RV+ERV+TV+IRV = VC+RV.

๐Ÿง’ Easy Explanation

Adding the cups gives 'capacities': IC = TV+IRV, EC = TV+ERV, FRC = ERV+RV. Vital Capacity is the most useful โ€” the biggest amount you can willingly move in or out. Total Lung Capacity is everything including the never-leaves part.

๐Ÿ“ NEET-style Questions
  1. Vital Capacity equals
    1. TV + IRV
    2. TV + ERV
    3. TV + IRV + ERV
    4. TV + IRV + ERV + RV
    Show answerAnswer: TV + IRV + ERV. VC excludes residual volume.
  2. Functional Residual Capacity is
    1. ERV + RV
    2. TV + IRV
    3. TV + RV
    4. VC + RV
    Show answerAnswer: ERV + RV. Air left after a normal expiration.
  3. Total Lung Capacity equals
    1. IRV+TV
    2. VC+RV
    3. FRC + IRV
    4. EC + RV
    Show answerAnswer: VC+RV. TLC = Vital Capacity + Residual Volume.
14.3

Exchange of Gases

1

Alveoli are the primary site of gas exchange. Exchange between blood and tissues also occurs by simple diffusion driven by pressure (concentration) gradients. Solubility of gases and thickness of the diffusion membrane affect the rate.

๐Ÿง’ Easy Explanation

Tiny balloons (alveoli) trade gases with blood by simple physics โ€” gas moves from where there's lots of it to where there's less, no pumps needed. Thin walls and gas-friendly water (solubility) speed it up.

๐Ÿ“ NEET-style Questions
  1. Exchange of gases occurs primarily by
    1. Active transport
    2. Simple diffusion
    3. Endocytosis
    4. Bulk flow
    Show answerAnswer: Simple diffusion. Driven by partial pressure gradients across thin alveolar membrane.
  2. Rate of gas exchange depends on
    1. Pressure gradient and solubility
    2. Membrane thickness
    3. Surface area
    4. All of these
    Show answerAnswer: All of these. Fick's law: rate โˆ area ร— ฮ”P / thickness.
  3. Primary site of gas exchange is
    1. Trachea
    2. Bronchi
    3. Bronchioles
    4. Alveoli
    Show answerAnswer: Alveoli. Alveoli have thin walls and dense capillary network.
2

Partial pressures (mm Hg): Atmospheric pOโ‚‚ โ‰ˆ 159, pCOโ‚‚ โ‰ˆ 0.3; Alveolar pOโ‚‚ โ‰ˆ 104, pCOโ‚‚ โ‰ˆ 40; Deoxygenated blood pOโ‚‚ โ‰ˆ 40, pCOโ‚‚ โ‰ˆ 45; Oxygenated blood pOโ‚‚ โ‰ˆ 95, pCOโ‚‚ โ‰ˆ 40; Tissues pOโ‚‚ โ‰ˆ 40, pCOโ‚‚ โ‰ˆ 45.

๐Ÿง’ Easy Explanation

Each gas has its own 'pressure number' that says how much of it is there. Oโ‚‚ is high in alveoli (104) and low in tissues (40) โ€” so it flows from alveoli to tissues. COโ‚‚ is the opposite โ€” high in tissues (45) and low in alveoli (40) โ€” so it flows out.

๐Ÿ“ NEET-style Questions
  1. Partial pressure of Oโ‚‚ in alveoli is approximately (mm Hg)
    1. 40
    2. 95
    3. 104
    4. 159
    Show answerAnswer: 104. Slightly less than atmospheric because of mixing with residual air.
  2. pCOโ‚‚ in tissues is approximately
    1. 0.3
    2. 40
    3. 45
    4. 159
    Show answerAnswer: 45. Higher than in blood, allowing COโ‚‚ to diffuse into the blood.
  3. Difference between atmospheric and alveolar pOโ‚‚ is approximately
    1. 55 mm Hg
    2. 100 mm Hg
    3. 159 mm Hg
    4. 0 mm Hg
    Show answerAnswer: 55 mm Hg. 159 โˆ’ 104 = 55 mm Hg.
3

Solubility of COโ‚‚ is 20โ€“25 times higher than that of Oโ‚‚, so even with a tiny pressure difference COโ‚‚ diffuses much faster across the membrane.

๐Ÿง’ Easy Explanation

COโ‚‚ swims through the watery membrane much more easily than Oโ‚‚ โ€” about 20 to 25 times faster โ€” so even a small push gets it across.

๐Ÿ“ NEET-style Questions
  1. Solubility of COโ‚‚ in blood compared to Oโ‚‚ is
    1. Equal
    2. 20โ€“25 times higher
    3. Half
    4. 100 times higher
    Show answerAnswer: 20โ€“25 times higher. High solubility lets COโ‚‚ transfer fast despite small gradient.
  2. Why does COโ‚‚ diffuse faster than Oโ‚‚?
    1. Higher pressure gradient
    2. Higher solubility
    3. Larger molecule
    4. Same speed
    Show answerAnswer: Higher solubility. Pressure gradient for Oโ‚‚ is actually larger โ€” but COโ‚‚'s solubility wins.
  3. If membrane thickness doubles, diffusion rate
    1. Doubles
    2. Halves
    3. Stays same
    4. Becomes zero
    Show answerAnswer: Halves. Rate โˆ 1/thickness.
4

The diffusion membrane has three layers: thin squamous epithelium of alveoli, endothelium of alveolar capillaries, and basement substance in between. Total thickness < 1 mm. This thin barrier favours rapid gas exchange.

๐Ÿง’ Easy Explanation

The wall between air and blood is super thin โ€” three paper-thin layers stacked, all under a millimetre. That's why gases zip across so easily.

๐Ÿ“ NEET-style Questions
  1. Diffusion membrane consists of
    1. 1 layer
    2. 2 layers
    3. 3 layers
    4. 4 layers
    Show answerAnswer: 3 layers. Alveolar epithelium + basement substance + capillary endothelium.
  2. Total thickness of the alveolar diffusion membrane is
    1. Much less than 1 mm
    2. About 1 cm
    3. About 1 m
    4. Variable
    Show answerAnswer: Much less than 1 mm. Standard NCERT value.
  3. The squamous epithelium of alveoli is
    1. Thick
    2. Thin
    3. Ciliated
    4. Glandular
    Show answerAnswer: Thin. Thinness is essential for efficient diffusion.
14.4

Transport of Gases

1

Blood transports Oโ‚‚ and COโ‚‚. About 97% of Oโ‚‚ is carried by RBCs and 3% dissolved in plasma. About 20โ€“25% of COโ‚‚ is carried by RBCs (as carbamino-haemoglobin), 70% as bicarbonate (HCOโ‚ƒโป) and 7% dissolved in plasma.

๐Ÿง’ Easy Explanation

Blood is the delivery truck. Oโ‚‚ rides almost entirely inside red blood cells (97%). COโ‚‚ takes three rides โ€” mostly as bicarbonate in plasma (70%), some stuck to haemoglobin (20-25%), a little dissolved (7%).

๐Ÿ“ NEET-style Questions
  1. Percentage of Oโ‚‚ carried by RBCs is approximately
    1. 50%
    2. 70%
    3. 85%
    4. 97%
    Show answerAnswer: 97%. 97% bound to haemoglobin; 3% dissolved in plasma.
  2. COโ‚‚ is mainly carried in blood as
    1. Bicarbonate
    2. Carbamino-haemoglobin
    3. Dissolved COโ‚‚
    4. Carbonic acid
    Show answerAnswer: Bicarbonate. About 70% of COโ‚‚ travels as HCOโ‚ƒโป.
  3. Approximate percentage of COโ‚‚ as carbamino-haemoglobin
    1. 7%
    2. 20โ€“25%
    3. 70%
    4. 100%
    Show answerAnswer: 20โ€“25%. Carbamino-haemoglobin carries 20โ€“25% of COโ‚‚.
2

Haemoglobin is a red, iron-containing pigment in RBCs. Each Hb molecule can carry up to 4 molecules of Oโ‚‚ reversibly to form oxyhaemoglobin. Binding depends mainly on pOโ‚‚; pCOโ‚‚, Hโบ and temperature also affect it.

๐Ÿง’ Easy Explanation

Hb is like a 4-seater bus โ€” each molecule can carry up to 4 oxygens. The bus loads up when pOโ‚‚ is high (in the lungs) and drops off passengers when pOโ‚‚ is low (in tissues).

๐Ÿ“ NEET-style Questions
  1. Each Hb molecule can carry up to
    1. 1
    2. 2
    3. 3
    4. 4
    Show answerAnswer: 4. Four haem groups bind four Oโ‚‚.
  2. Hb is rich in
    1. Calcium
    2. Zinc
    3. Iron
    4. Magnesium
    Show answerAnswer: Iron. Feยฒโบ in haem binds Oโ‚‚ reversibly.
  3. Binding of Oโ‚‚ to Hb is primarily related to
    1. pCOโ‚‚
    2. pOโ‚‚
    3. Temperature
    4. Hโบ
    Show answerAnswer: pOโ‚‚. High pOโ‚‚ โ†’ more loading.
3

The Oxygen Dissociation Curve is sigmoid. In alveoli (high pOโ‚‚, low pCOโ‚‚, low Hโบ, lower T) โ†’ favours formation of oxyhaemoglobin. In tissues (low pOโ‚‚, high pCOโ‚‚, high Hโบ, higher T) โ†’ favours dissociation. Every 100 mL of oxygenated blood delivers about 5 mL Oโ‚‚ to tissues.

๐Ÿง’ Easy Explanation

The curve looks like a stretched 'S'. In lungs, conditions favour loading Oโ‚‚ onto Hb; in working tissues, conditions favour unloading. Acidity, heat, and COโ‚‚ all push Oโ‚‚ off Hb (Bohr effect).

๐Ÿ“ NEET-style Questions
  1. Oxygen dissociation curve is
    1. Linear
    2. Hyperbolic
    3. Sigmoid
    4. Parabolic
    Show answerAnswer: Sigmoid. S-shape due to cooperative binding of Oโ‚‚.
  2. In tissues, the curve shifts
    1. Left
    2. Right
    3. No shift
    4. Inverted
    Show answerAnswer: Right. High COโ‚‚/Hโบ/T = right shift = Oโ‚‚ released more easily (Bohr effect).
  3. 100 mL of oxygenated blood delivers approximately
    1. 1 mL
    2. 5 mL
    3. 20 mL
    4. 50 mL
    Show answerAnswer: 5 mL. Tissues receive about 5 mL Oโ‚‚ per 100 mL blood under normal conditions.
4

COโ‚‚ transport via bicarbonate: at the tissue, COโ‚‚ + Hโ‚‚O โ‡Œ Hโ‚‚COโ‚ƒ โ‡Œ HCOโ‚ƒโป + Hโบ catalysed by carbonic anhydrase in RBCs. At alveoli the reaction reverses to release COโ‚‚. Every 100 mL of deoxygenated blood delivers about 4 mL COโ‚‚ to alveoli.

๐Ÿง’ Easy Explanation

COโ‚‚ at tissues gets quickly turned into HCOโ‚ƒโป by a fast enzyme (carbonic anhydrase) inside red cells, then travels in plasma. In the lungs the enzyme reverses it back to COโ‚‚ to be breathed out.

๐Ÿ“ NEET-style Questions
  1. Enzyme catalysing COโ‚‚ + Hโ‚‚O โ‡Œ Hโ‚‚COโ‚ƒ is
    1. Catalase
    2. Carbonic anhydrase
    3. Cytochrome c
    4. Aldolase
    Show answerAnswer: Carbonic anhydrase. Located mainly in RBCs.
  2. 100 mL deoxygenated blood delivers approximately
    1. 1 mL COโ‚‚
    2. 4 mL COโ‚‚
    3. 20 mL COโ‚‚
    4. 75 mL COโ‚‚
    Show answerAnswer: 4 mL COโ‚‚. Standard NCERT value.
  3. Bohr effect refers to
    1. Acidity decreases Oโ‚‚ binding
    2. Acidity increases Oโ‚‚ binding
    3. Heat increases binding
    4. Temperature decreases binding
    Show answerAnswer: Acidity decreases Oโ‚‚ binding. Higher Hโบ/COโ‚‚ shifts curve right โ†’ Oโ‚‚ released to tissues.
14.5

Regulation of Respiration

1

The respiratory rhythm centre in the medulla primarily maintains respiratory rhythm. The pneumotaxic centre in the pons can moderate it by reducing inspiration duration.

๐Ÿง’ Easy Explanation

Brain has two control rooms โ€” the medulla sets the basic in-and-out rhythm, the pons can change how long each breath lasts.

๐Ÿ“ NEET-style Questions
  1. Respiratory rhythm centre is located in
    1. Pons
    2. Cerebellum
    3. Medulla
    4. Cerebrum
    Show answerAnswer: Medulla. Medulla oblongata houses the main respiratory centre.
  2. Pneumotaxic centre is in the
    1. Medulla
    2. Pons
    3. Spinal cord
    4. Hypothalamus
    Show answerAnswer: Pons. Pons modulates the medullary rhythm.
  3. Pneumotaxic centre can
    1. Reduce duration of inspiration
    2. Increase TV
    3. Increase RV
    4. Stop breathing
    Show answerAnswer: Reduce duration of inspiration. It alters respiratory rate by shortening inspiration.
2

A chemosensitive area adjacent to the rhythm centre is highly sensitive to COโ‚‚ and Hโบ. Increased levels activate it; it signals the rhythm centre to eliminate COโ‚‚. Receptors at the aortic arch and carotid artery also detect COโ‚‚/Hโบ. Role of Oโ‚‚ in regulation is insignificant.

๐Ÿง’ Easy Explanation

Tiny sensors in the brain (and major arteries) keep watch on COโ‚‚ and acid levels in blood. If COโ‚‚ rises, breathing speeds up automatically. Oxygen has almost no role in this control.

๐Ÿ“ NEET-style Questions
  1. Chemosensitive area is sensitive to
    1. Oโ‚‚ and Nโ‚‚
    2. COโ‚‚ and Hโบ
    3. Glucose
    4. Water
    Show answerAnswer: COโ‚‚ and Hโบ. Detects rise in COโ‚‚ and acidity.
  2. Peripheral chemoreceptors are present in
    1. Aortic arch and carotid artery
    2. Lungs
    3. Liver
    4. Kidney
    Show answerAnswer: Aortic arch and carotid artery. These send signals to the rhythm centre.
  3. Role of oxygen in respiratory regulation is
    1. Major
    2. Insignificant
    3. Equal to COโ‚‚
    4. Only at high altitudes
    Show answerAnswer: Insignificant. NCERT statement: Oโ‚‚ has insignificant regulatory role.
14.6

Disorders of the Respiratory System

1

Asthma โ€” difficulty in breathing causing wheezing due to inflammation of bronchi and bronchioles. Emphysema โ€” chronic disorder where alveolar walls are damaged, reducing respiratory surface; major cause is cigarette smoking.

๐Ÿง’ Easy Explanation

Asthma narrows the small air pipes so air whistles through them (wheeze). Emphysema breaks the alveolar walls โ€” less surface for swapping gases. Smoking is the worst trigger for emphysema.

๐Ÿ“ NEET-style Questions
  1. Asthma involves inflammation of
    1. Alveoli
    2. Trachea
    3. Bronchi and bronchioles
    4. Pleura
    Show answerAnswer: Bronchi and bronchioles. Narrowed airways cause wheezing.
  2. Emphysema damages
    1. Trachea
    2. Larynx
    3. Alveolar walls
    4. Pleura
    Show answerAnswer: Alveolar walls. Reduces total surface area for gas exchange.
  3. Major cause of emphysema is
    1. Bacterial infection
    2. Cigarette smoking
    3. Cold air
    4. Pollution
    Show answerAnswer: Cigarette smoking. Smoking destroys elastic alveolar tissue.
2

Occupational respiratory disorders โ€” long exposure to dust (e.g., stone-grinding) causes inflammation that progresses to fibrosis (proliferation of fibrous tissues) and serious lung damage. Workers should wear protective masks.

๐Ÿง’ Easy Explanation

Working in dusty places like stone-grinding plants can clog and scar the lungs with fibres over years. Masks are essential.

๐Ÿ“ NEET-style Questions
  1. Long exposure to industrial dust causes
    1. Asthma
    2. Emphysema
    3. Fibrosis
    4. Pneumonia
    Show answerAnswer: Fibrosis. Fibrous tissue proliferation damages lungs.
  2. Occupational respiratory disorders are common in
    1. Office workers
    2. Stone-grinders
    3. Teachers
    4. Cooks
    Show answerAnswer: Stone-grinders. Grinding/stone-breaking work produces fine dust.
  3. Prevention of occupational lung disorders includes
    1. Exercise
    2. Vaccination
    3. Wearing protective masks
    4. Eating fibre-rich diet
    Show answerAnswer: Wearing protective masks. Physical barrier to dust inhalation.
โš 

Exceptions to Remember

๐Ÿงช

Scientists & Key Contributions

Christian Bohr (1855โ€“1911)

Danish physiologist; discovered the Bohr effect โ€” COโ‚‚ and Hโบ shift the Oโ‚‚-dissociation curve to the right, releasing Oโ‚‚ in tissues.

John Scott Haldane (1860โ€“1936)

Studied gas exchange in lungs and respiratory regulation by COโ‚‚. The 'Haldane effect' is named after him.

Felix Hoppe-Seyler

Crystallised haemoglobin and coined the name; founded modern biochemistry of respiratory pigments.

Alfonso Corti (1822โ€“1888)

Italian anatomist who described the organ of Corti in the cochlea; unit chapter opener.

๐Ÿ“Œ

Key Examples & Values

Example / ValueSignificance
Tidal volume (TV)500 mL per breath at rest
Inspiratory Reserve Volume (IRV)2500โ€“3000 mL
Expiratory Reserve Volume (ERV)1000โ€“1100 mL
Residual Volume (RV)1100โ€“1200 mL
Vital Capacity (VC)โ‰ˆ 4000โ€“4500 mL = ERV + TV + IRV
Total Lung Capacity (TLC)โ‰ˆ 5000โ€“6000 mL = VC + RV
Resting respiratory rate12โ€“16 breaths per minute
Atmospheric pOโ‚‚ / pCOโ‚‚159 / 0.3 mm Hg
Alveolar pOโ‚‚ / pCOโ‚‚104 / 40 mm Hg
Tissue pOโ‚‚ / pCOโ‚‚40 / 45 mm Hg
Solubility ratio COโ‚‚ : Oโ‚‚โ‰ˆ 20โ€“25 : 1
Hb molecules per Oโ‚‚ carried4 Oโ‚‚ per Hb (max)
Oxygen carried per 100 mL bloodโ‰ˆ 5 mL delivered to tissues
COโ‚‚ delivered per 100 mL deoxygenated bloodโ‰ˆ 4 mL to alveoli
Distribution of COโ‚‚ in blood70% bicarbonate, 20โ€“25% carbamino-Hb, 7% dissolved
Distribution of Oโ‚‚ in blood97% with Hb, 3% dissolved in plasma
๐Ÿ“

NCERT Exercises โ€” Explained & Answered

Q1Define vital capacity. What is its significance?

Vital Capacity (VC) is the maximum volume of air a person can breathe out after a forced inspiration (or breathe in after a forced expiration). VC = TV + IRV + ERV โ‰ˆ 4000โ€“4500 mL. Significance: reflects strength of respiratory muscles and lung elasticity; reduced in restrictive disorders (fibrosis) and obstructive disorders (emphysema).

Q2State the volume of air remaining in the lungs after a normal breathing.

After a normal (tidal) expiration, the air remaining is the Functional Residual Capacity (FRC) = ERV + RV โ‰ˆ 2100โ€“2300 mL. The lungs are never fully empty during normal breathing.

Q3Diffusion of gases occurs in the alveolar region only and not in the other parts of respiratory system. Why?

Only the alveoli have (i) extremely thin walls (single layer of squamous epithelium), (ii) rich capillary network, and (iii) huge surface area. The bronchi, bronchioles and trachea are lined by thicker tissue with cartilage/cilia/mucous glands and lack pulmonary capillary network โ€” they are part of the conducting zone.

Q4What are the major transport mechanisms for COโ‚‚? Explain.

Three pathways: (a) Bicarbonate (70%) โ€” COโ‚‚ + Hโ‚‚O โ‡Œ Hโ‚‚COโ‚ƒ โ‡Œ HCOโ‚ƒโป + Hโบ via carbonic anhydrase; HCOโ‚ƒโป travels in plasma. (b) Carbamino-haemoglobin (20โ€“25%) โ€” bound to globin part of Hb. (c) Dissolved in plasma (7%). At alveoli all reactions reverse and COโ‚‚ is released.

Q5Compare atmospheric and alveolar pOโ‚‚/pCOโ‚‚.

Option (ii) is correct: pOโ‚‚ higher, pCOโ‚‚ lesser in atmospheric air than in alveolar air. Atmospheric pOโ‚‚ = 159 vs alveolar 104; atmospheric pCOโ‚‚ = 0.3 vs alveolar 40 mm Hg.

Q6Explain the process of inspiration under normal conditions.

Diaphragm contracts and flattens, increasing the antero-posterior diameter of the thoracic cavity. Simultaneously the external intercostal muscles contract, lifting the ribs and sternum up and outward โ†’ dorso-ventral diameter increases. Overall thoracic and pulmonary volumes rise; intra-pulmonary pressure falls below atmospheric โ†’ air rushes in.

Q7How is respiration regulated?

The respiratory rhythm centre in the medulla maintains baseline rhythm. The pneumotaxic centre in the pons can shorten inspiration. A chemosensitive area near the rhythm centre detects rise in COโ‚‚/Hโบ; peripheral chemoreceptors at the aortic arch and carotid artery do the same. Oโ‚‚ has insignificant role.

Q8What is the effect of pCOโ‚‚ on oxygen transport?

High pCOโ‚‚ (as in tissues) reduces the affinity of Hb for Oโ‚‚ โ€” the dissociation curve shifts to the right (Bohr effect). This helps unload Oโ‚‚ where it is needed. Low pCOโ‚‚ (alveoli) does the opposite โ€” favours loading of Oโ‚‚.

Q9What happens to the respiratory process in a man going up a hill?

At higher altitudes atmospheric pOโ‚‚ falls. Lower pOโ‚‚ โ†’ less oxygen loading on Hb โ†’ tissue hypoxia. Body responds by hyperventilation (faster, deeper breathing) and over time increases RBC count / Hb to improve Oโ‚‚-carrying capacity (acclimatisation). The person may experience fatigue, dizziness and altitude sickness.

Q10What is the site of gaseous exchange in an insect?

Gas exchange occurs through a network of tracheal tubes opening at spiracles on the body wall. Tracheoles deliver Oโ‚‚ directly to tissues โ€” blood plays no role in Oโ‚‚ transport in insects.

Q11Define oxygen dissociation curve. Can you suggest any reason for its sigmoidal pattern?

Oxygen dissociation curve = plot of % saturation of Hb (y-axis) vs pOโ‚‚ (x-axis). Sigmoid (S-shaped) because binding of one Oโ‚‚ molecule to a Hb subunit increases the affinity of remaining sites for Oโ‚‚ โ€” cooperative binding. Steep middle portion enables rapid loading at moderate pOโ‚‚.

Q12Have you heard about hypoxia? Try to gather information about it, and discuss with your friends.

Hypoxia = oxygen deficiency at tissue level. Types: hypoxic (low arterial pOโ‚‚), anaemic (low Hb), stagnant (poor circulation), histotoxic (cells cannot use Oโ‚‚, e.g., cyanide poisoning). Symptoms: confusion, breathlessness, blue lips, fatigue. Treated by Oโ‚‚ therapy and correcting cause.

Q13Distinguish between (a) IRV and ERV (b) Inspiratory and Expiratory capacity (c) Vital capacity and Total lung capacity.

(a) IRV โ€” extra air inspired forcibly (~2500โ€“3000 mL); ERV โ€” extra air expired forcibly (~1000โ€“1100 mL). (b) IC = TV + IRV (~3500 mL); EC = TV + ERV (~1500 mL). (c) VC = ERV + TV + IRV โ‰ˆ 4500 mL; TLC = VC + RV โ‰ˆ 5500โ€“6000 mL.

Q14What is Tidal volume? Find out the Tidal volume (approximate value) for a healthy human in an hour.

Tidal volume = volume of air inspired or expired during normal quiet breathing โ‰ˆ 500 mL. At 12 breaths/min: per hour = 500 mL ร— 12 ร— 60 = 360 000 mL = 360 L (about 6 L/min ร— 60).
๐Ÿ†

High-Yield Points for NEET

  1. Trachea bifurcates at the level of the 5th thoracic vertebra into two primary bronchi.
  2. Pleural fluid reduces friction on the lung surface.
  3. Conducting part: nostrils โ†’ terminal bronchioles. Respiratory part: alveoli + alveolar ducts.
  4. Inspiration is ACTIVE (muscles contract); quiet expiration is PASSIVE (muscles relax).
  5. Diaphragm contributes to antero-posterior expansion; intercostals to dorso-ventral.
  6. Memorise: TV 500, IRV 3000, ERV 1100, RV 1200; VC โ‰ˆ 4500, TLC โ‰ˆ 6000 mL.
  7. Atmospheric, alveolar and tissue pOโ‚‚: 159, 104, 40 mm Hg.
  8. Atmospheric, alveolar and tissue pCOโ‚‚: 0.3, 40, 45 mm Hg.
  9. Oโ‚‚ in blood: 97% as oxyhaemoglobin, 3% dissolved.
  10. COโ‚‚ in blood: 70% bicarbonate, 20โ€“25% carbamino-Hb, 7% dissolved.
  11. Carbonic anhydrase (in RBCs) catalyses both forward and reverse reactions of COโ‚‚ โ‡Œ HCOโ‚ƒโป.
  12. Oxygen dissociation curve is sigmoid. Right shift (Bohr) helps tissues; left shift (in alveoli) loads Oโ‚‚.
  13. Each Hb molecule binds up to 4 Oโ‚‚.
  14. Respiratory rhythm centre โ€” medulla; pneumotaxic centre โ€” pons; chemosensitive area โ€” sensitive to COโ‚‚ + Hโบ.
  15. Oโ‚‚ has negligible direct role in respiratory rhythm regulation.
  16. Asthma โ€” inflammation of bronchi/bronchioles. Emphysema โ€” alveolar wall damage (smoking).
  17. Solubility of COโ‚‚ in blood is 20โ€“25 times that of Oโ‚‚.
  18. Diffusion membrane = 3 layers + total thickness < 1 mm.
  19. VC reflects pulmonary health โ€” falls in restrictive (fibrosis) and obstructive (emphysema) diseases.
  20. Aortic arch and carotid body sensors detect blood COโ‚‚/Hโบ for reflex regulation.

โš–๏ธ Quick Comparisons โ€” Side-by-Side Reference

VS Inspiration vs Expiration

PropertyInspirationExpiration
Type at restActivePassive
DiaphragmContracts and flattensRelaxes; dome-shaped
External intercostalsContract; ribs liftRelax; ribs lower
Thoracic volumeIncreasesDecreases
Intra-pulmonary pressureLess than atmosphericSlightly greater than atmospheric
Air flowAtmosphere โ†’ lungsLungs โ†’ atmosphere

VS IRV vs ERV

PropertyIRVERV
Full nameInspiratory Reserve VolumeExpiratory Reserve Volume
DefinitionExtra air inspired forcibly after normal inspirationExtra air expired forcibly after normal expiration
Volume2500โ€“3000 mL1000โ€“1100 mL
DirectionInOut

VS Inspiratory Capacity (IC) vs Expiratory Capacity (EC)

PropertyICEC
FormulaTV + IRVTV + ERV
Value~3500 mL~1500 mL
MeaningTotal inspired after normal expirationTotal expired after normal inspiration

VS Vital Capacity (VC) vs Total Lung Capacity (TLC)

PropertyVCTLC
FormulaERV + TV + IRVVC + RV
Value~4500 mL~5500โ€“6000 mL
Includes RV?NoYes
Clinical usePulmonary function indexTotal air-containing capacity

VS Conducting Part vs Respiratory Part

PropertyConductingRespiratory / Exchange
StructuresNostrils โ†’ terminal bronchiolesAlveoli + alveolar ducts
FunctionTransport, clean, humidify, warm airGas diffusion (Oโ‚‚/COโ‚‚)
CartilagePresent in mostAbsent
Cilia / mucusPresentAbsent

VS Oโ‚‚ vs COโ‚‚ โ€” Partial Pressures (mm Hg)

RegionpOโ‚‚pCOโ‚‚
Atmospheric air1590.3
Alveolar air10440
Deoxygenated blood4045
Oxygenated blood9540
Tissues4045

Gradient is OPPOSITE for Oโ‚‚ and COโ‚‚. NEET classic.

VS Oxygen vs Carbon Dioxide Transport

PropertyOxygenCarbon Dioxide
% in plasma (dissolved)3%7%
% with Hb97% (oxyhaemoglobin)20โ€“25% (carbamino-Hb)
% as bicarbonate070%
SolubilityLow20โ€“25ร— higher than Oโ‚‚
Loading siteAlveoliTissues

VS Bohr effect โ€” Tissue vs Alveolar conditions

PropertyTissuesAlveoli
pOโ‚‚LowHigh
pCOโ‚‚HighLow
Hโบ concentrationHighLow
TemperatureHigherLower
Effect on Oโ‚‚โ€“HbDissociationFormation
Curve shiftRightLeft

VS Respiratory Rhythm Centre vs Pneumotaxic Centre

PropertyRhythm CentrePneumotaxic Centre
LocationMedullaPons
Primary roleSets basal respiratory rhythmModulates rhythm (shortens inspiration)
EffectDrives breathingAlters respiratory rate

VS Asthma vs Emphysema

PropertyAsthmaEmphysema
CauseInflammation, allergensCigarette smoking, chronic exposure
Site of damageBronchi and bronchiolesAlveolar walls
ReversibilityReversible (with bronchodilators)Irreversible
Main symptomWheezing, breathing difficultyBreathlessness, decreased surface area

VS Breathing in different animals

AnimalRespiratory organType
Sponges, coelenterates, flatwormsBody surfaceSimple diffusion
EarthwormMoist cuticleCutaneous diffusion
InsectsTracheal tubesTracheal respiration
Aquatic arthropods, molluscsGillsBranchial respiration
FishesGillsBranchial
FrogsLungs + moist skinPulmonary + cutaneous
Reptiles, birds, mammalsLungsPulmonary
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